An aircraft with a mass of 5000 kg takes off from sea level with a forward speed of 50 m/s and starts to climb with a climb angle of 15 degree. What is the rate of climb and excess thrust available at the start of the climb?
An aircraft with a mass of 5000 kg takes off from sea level with a forward speed of 50 m/s and starts to climb with a climb angle of 15 ^{\circ}. What is the rate of climb and excess thrust available at the start of the climb?
The aircraft is climbing with an climb angle of 15^{\circ} .Here forward speed is 50 m/s.From the figure we can see that rate of climb will be given as Vsin\theta \\=50sin15^{\circ} \\=12.94\;m/s
Excess thrust is given as T-D=Wsin\theta
=5000\times 9.81 \times sin15^{\circ}
\\=12695.1 N
