The temperature field in a body varies according to the equation T(x,y)=x^{3}+4xy. Find the direction of fastest variation in temperature at the point (1,0).
The temperature field in a body varies according to the equation T(x,y)=x^{3}+4xy. Find the direction of fastest variation in temperature at the point (1,0).
The fastest variation of temperature will be given as \frac{\partial \phi}{\partial x}i+\frac{\partial\phi }{\partial y}j.
Here \phi is any function in terms of x and y.
\frac{\partial \phi}{\partial x}=\frac{\partial }{\partial x}\left ( x^{3}+4xy\right ) \\=3x^{2}+4y
\frac{\partial \phi }{\partial y}=\frac{\partial }{\partial y}\left ( x^{3} +4xy\right ) \\=4x
At point (1,0) its value will be 3x^{2}+4y=3(1^{2})+4(0)=3
and 4x=4(1)=4
=3i+4j
At this point its directional unit vector will be \frac{3i+4j}{\sqrt{3^{2}+4^{2}}} \\=\frac{3i+4j}{\sqrt{25}} \\=\frac{3i+4j}{5}
=0.6i+0.8j