The transition Reynolds number for flow over a flat plate is 5 x 10^5. What is the distance from the leading edge at which transition will occur for flow of water with a uniform velocity of 1m/s?
The transition Reynolds number for flow over a flat plate is \(5 \times 10^{5}\).What is the distance from the leading edge at which transition will occur for flow of water with a uniform velocity of \(1\;m/s\)? (For water ,the kinematic viscosity, \(\nu=0.858\times 10^{-6}\;m^{2}/s \).)
Here transition Reynolds number of the flat plate is given.We need to find the distance from the leading edge where the transition will occur.Reynolds number is the ratio of inertia force to viscous force.
In terms of kinematic viscosity Reynolds number is given as \[Re=\frac{uL}{\nu} \]
Here \(u=1 \;m/s\) and \(\nu=0.858\times 10^{-6}\;m^{2}/s\)
\[Re=\frac{uL}{\nu}
\\\Rightarrow 5\times 10^{5}=\frac{1\times L}{0.858\times 10^{-6}}
\\\Rightarrow L=0.429\approx 0.43\;m\]
