# A pitot tube of an airplane which is flying at an standard sea level measures a pressure of $$1.09 \times 10^{5} N/m^{2}$$. Find the velocity of the airplane.

A pitot tube of an airplane which is flying at an standard sea level measures a pressure of $$1.09 \times 10^{5} N/m^{2}$$. Find the velocity of the airplane.

Asked on 16th June 2021 in
• 1 Answer(s)

Pitot tube: It is a flow measurement device which is used to measure the fluid flow velocity. It is used to determine the velocity of an aircraft.

Pitot tube

Velocity is determined using the Bernoulli’s equation.

Total pressure = static pressure + dynamic pressure $p_{0}=p_{s} + \frac{1}{2}\rho V^{2}$$\Rightarrow V = \sqrt{\frac{2\left ( p_{0} – p_{s} \right )}{\rho }}$Here,$p_{0} = 1.09 \times 10^{5}\,N/m^{2}$$p_{s}=1.01 \times 10^{5}\, N/m^{2}$$\rho = 1.225\, kg/m^{3}$Therefore,$V=\sqrt{\frac{2\left ( 1.09\times 10^{5}-1.01\times 10^{5} \right )}{1.225}}=114.3\,m/s$

Answered on 1st July 2021.
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