# A pitot tube of an airplane which is flying at an standard sea level measures a pressure of $$1.09 \times 10^{5} N/m^{2}$$. Find the velocity of the airplane.

A pitot tube of an airplane which is flying at an standard sea level measures a pressure of $$1.09 \times 10^{5} N/m^{2}$$. Find the velocity of the airplane.

Asked on 16th June 2021 in
Total pressure = static pressure + dynamic pressure $p_{0}=p_{s} + \frac{1}{2}\rho V^{2}$$\Rightarrow V = \sqrt{\frac{2\left ( p_{0} – p_{s} \right )}{\rho }}$Here,$p_{0} = 1.09 \times 10^{5}\,N/m^{2}$$p_{s}=1.01 \times 10^{5}\, N/m^{2}$$\rho = 1.225\, kg/m^{3}$Therefore,$V=\sqrt{\frac{2\left ( 1.09\times 10^{5}-1.01\times 10^{5} \right )}{1.225}}=114.3\,m/s$