A Pitot tube on an airplane flying at standard sea level reads 1.07\times 10^{5}\; N/m^{2}. What is the velocity of the airplane?
A Pitot tube on an airplane flying at standard sea level reads 1.07\times 10^{5}\; N/m^{2}. What is the velocity of the airplane?
We need to find here the velocity of the airplane.P_{0}=P_{\infty}+\frac{1}{2}\rho V_{\infty}^{2} \\\Rightarrow V_{\infty}=\sqrt{\frac{2\left ( P_{0}-P_{\infty} \right )}{\rho }} \\=\sqrt{\frac{2\left ( 1.07-1.01 \right )\times 10^{5}}{1.23}} \\=98.8\;m/s
