# Consider an airplane flying at 620 mi/h at 35,000 ft. Calculate its energy height.

Consider an airplane flying at 620 mi/h at 35,000 ft. Calculate its energy height.

\(v = 620\left ( \frac{5280}{3600} \right ) = 909.333\,ft/s; g = 32.2\,ft/s^{2}\)

Energy height =

\[h+\frac{v^{2}}{2g}=35000 + \frac{909.333^{2}}{2\left ( 32.2 \right )}=47839.853\,ft\]