Find the inlet area of a ramjet engine, if the maximum thrust to be produced is 5000\, N at sea level at an inlet velocity of 300\,m/s. The exit velocity, area and pressure are 650\,m/s, 0.08\,m^2 and 104000\,N/m^2.

Find the inlet area of a ramjet engine, if the maximum thrust to be produced is 5000\, N at sea level at an inlet velocity of 300\,m/s. The exit velocity, area and pressure are 650\,m/s, 0.08\,m^2 and 104000\,N/m^2.

Kisan Kumar Asked on 12th February 2021 in Propulsion.
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    Thrust produced by the engine is

    T = \dot m\left( {{V_e} – {V_\infty }} \right) + \left( {{P_e} – {P_\infty }} \right){A_e}

    \Rightarrow 5000 = \dot m\left( {650 – 300} \right) + \left( {104000 – 101325} \right)0.08

    \Rightarrow \dot m = 13.7\,kg/s

    and,

    \dot m = {\rho _\infty }{V_\infty }{A_i}

    \Rightarrow {13.7} = 1.225 \times 300 \times {A_i}

    \Rightarrow {A_i} = \frac{{13.7}}{{367.5}} = 0.037{m^2}

    Kumar59 Answered on 23rd February 2021.
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