Show that a uniform flow with velocity {V_\infty } is a physically possible incompressible flow and is irrotational.

Show that a uniform flow with velocity {V_\infty } is a physically possible incompressible flow and is irrotational.

techAir Asked on 31st December 2018 in Aerodynamics.
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    For a uniform flow {V_\infty } = u = {\rm{constant}}\,\,{\rm{;}}\,\,\mathop V\limits^ \to   = {V_\infty }\mathop i\limits^ \to  Divergence of velocity field\nabla  \cdot \mathop V\limits^ \to   = \frac{{\partial u}}{{\partial x}} + \frac{{\partial v}}{{\partial y}} + \frac{{\partial w}}{{\partial z}} = 0 + 0 + 0 = 0Therefore, it shows that it is a physically possible incompressible flow.

    Also, curl of velocity field \nabla  \times \mathop V\limits^ \to   = \left| {\begin{array}{*{20}{c}}{\mathop i\limits^ \to  }&{\mathop j\limits^ \to  }&{\mathop k\limits^ \to  }\\{\frac{\partial }{{\partial x}}}&{\frac{\partial }{{\partial y}}}&{\frac{\partial }{{\partial z}}}\\u&v&w\end{array}} \right| = \mathop i\limits^ \to  \left( {0 – 0} \right) – \mathop j\limits^ \to  \left( {0 – \frac{{\partial u}}{{\partial x}}} \right) + \mathop k\limits^ \to  \left( {0 – \frac{{\partial u}}{{\partial y}}} \right)\nabla  \times \mathop V\limits^ \to   = 0This shows that the flow is irrotational.

    Worldtech Answered on 31st December 2018.
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